Saturday, February 28, 2015

40 Pounds - Light as a Feather?

I just watched an awesome YouTube video by Veritasium, an awesome YouTube channel similar to Vsauce, that specializes in physics and cool demonstrations. In the video, we were shown a 40-pound barbell, but attached only on one side. The metal bar used to lift the weight, instead of having a round 20-pound weight at either side, had only one 40-pound weight, on the left side.

Even when a muscular bodybuilder was brought in, nobody could lift this strange barbell from the side opposite the round weight, and keep it horizontal. Why? Simple mechanics tells us that torque, τ, is equal to the lever arm, b, times the force, F:
Having a large weight, F = 40 lbs., and a relatively long lever arm, b = 3 ft., τ = 120 lbs. × ft. In order to counteract this huge torque against your hand and keep the bar level, your hand, with a width = 5 in. 0.416 ft., would have to apply a huge force. From the first formula, we can derive that
,
so the force your hand would need is 120 lbs. × ft. ÷ 0.42 ft. 290 lbs.. In conclusion, in order to hold this barbell horizontally, you would have to be able to lift almost 300 lbs. with that hand.
The next thing that happened in the video is that the circular weight, which had been attached as a flywheel to the bar, was spun up to about 3000 rpm., the weight being about 5 in. in radius. When the barbell is released, and held up only from the arm on the side opposite the spinning weight, the spinning weight exhibits a few properties of a gyroscope.
First off, it opposes any change in its angular orientation. The first thing we need to calculate this is the weight’s moment of inertia, l, given by
where M is the mass, 40 lbs., and R is the radius, 5 in.. This gives a moment of inertia of 500 lbs. × ft2.. The next thing we need is the angular velocity, α, given by
where F is the gravitational attraction, 32.2 ft. / second2, M is the mass, and R is the radius. This formula gives us an angular velocity of 0.322. Next, we must find the angular velocity, ω, which is, in this case,
which means that ω 9424.78 rad. × sec.-1.
Now, we can finally calculate the torque that the spinning weight exerts upon the bar, using the following formula:
This gives us a torque, τ, of about 44,413,239,185.2 lbs. of force. WOW! Over 4.4 BILLION POUNDS of force! That’s how strongly the spinning weight is holding itself up!
So, when the bar is being held from the side opposite the spinning weight, any gravitational pull on the weight is cancelled out instantly by its enormous opposition force. The 40-pound barbell has become literally lighter than a feather!
For more information, visit: http://en.wikipedia.org/wiki/Gyroscope

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